Question

a man with a 45kg mass dove 12m from a building into 0.32m of water. a)what was his kinetic energy when he hit the water?
b)what average net force was exerted on him when he stopped?

Answer 1

v = sqrt (2 g h) = sqrt (2 * 9.81*12)

a ) Ke = (1/2)(45) v^2

b ) stops in .32 m
work = Force * .32 = Ke from part a