Asked by sam
a man with a 45kg mass dove 12m from a building into 0.32m of water. a)what was his kinetic energy when he hit the water?
b)what average net force was exerted on him when he stopped?
b)what average net force was exerted on him when he stopped?
Answers
Answered by
Damon
v = sqrt (2 g h) = sqrt (2 * 9.81*12)
a ) Ke = (1/2)(45) v^2
b ) stops in .32 m
work = Force * .32 = Ke from part a
a ) Ke = (1/2)(45) v^2
b ) stops in .32 m
work = Force * .32 = Ke from part a
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