A 45kg block slides down an incline that is angled at 41 degrees. If the coefficient of kinetic friction between the block and the incline is 0.45 what is the block's acceleration?

2 answers

normal component of weight = 45*9.81* cos 41
so friction force = 0.45* 45*9.81*cos 41

component of weight down slope = 45*9.81 * sin 41

so
45 a = 45*9.81*sin 41 - .45*45*9.81*cos 41
or
a = 9.81* (sin 41 - .45 cos 41)
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