Asked by Final Water Temperature
A 45kg sample of water absorbs 364kJ of heat. If the water was initially at 28.2 Celcius, what is its final temperature? How do I figure this out....HELP!
Answers
Answered by
DrBob222
Note the correct spelling of celsius.
364,000 = mass H2O x specific heat H2O x (Tfinal-Tinitial). Substitute and solve for Tf.
364,000 = mass H2O x specific heat H2O x (Tfinal-Tinitial). Substitute and solve for Tf.
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