Asked by Final Water Temperature
                A 45kg sample of water absorbs 364kJ of heat.  If the water was initially at 28.2 Celcius, what is its final temperature?  How do I figure this out....HELP!
            
            
        Answers
                    Answered by
            DrBob222
            
    Note the correct spelling of celsius.
364,000 = mass H2O x specific heat H2O x (Tfinal-Tinitial). Substitute and solve for Tf.
    
364,000 = mass H2O x specific heat H2O x (Tfinal-Tinitial). Substitute and solve for Tf.
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