Asked by Carol

A 45kg sample of water absorbs 367kJ of heat. If the water was initially 24.8ºC, what is final temperature? Please explain steps. Thanks
Answered by bobpursley
heat=mass*c*(tf-ti)
steps? You know heat, mass, ti. The only issue is the specific heat of water UNITS. YOu need c in kJ/kgC
Answered by carol
mass of water= 367,000 x specific heat (24.8?) x Tf (how do i find this? what part of the question tells me?)
Answered by bobpursley
Lord:
mass water=45kg
heat=367kJ
c= 4.17kJ/kgC
Ti=24.8C

367kJ=45kg*4.17kJ/kgC*(Tf-20)

Tf-20=367/(45*4.17)
Tf=367/(45*4.17) +20
Answered by carol
I don't appreciate the LORD: if Jesus had anything to do with it I would NOT have to take chemistry!
Answered by Jack
where did you find the C?
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