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some highschool kid ya kno
Answers (7)
maybe this help? vf-vi=at, so find that negative number then divide by two and it will give u |vi| make it positive vf =0 at the top, so 0^2=vi^2 + 2a ∆x then -(vi^2)/(2a){should be 19.6}= ∆x
vf-vi=at, so find that negative number then divide by two and it will give u |vi| make it positive vf =0 at the top, so 0^2=vi^2 + 2a ∆x then -(vi^2)/(2a){should be 19.6}= ∆x
vf-vi=at, so find that negative number then divide by two and it will give u |vi| make it positive vf =0 at the top, so 0^2=vi^2 + 2a ∆x then -(vi^2)/(2a){should be 19.6}= ∆x
if yalll didnt understand, here also b/c why not vf-vi=at, so find that negative number then divide by two and it will give u |vi| make it positive vf =0 at the top, so 0^2=vi^2 + 2a ∆x then -(vi^2)/(2a){should be 19.6}= ∆x
idk what he wrote so here ya go vf-vi=at, so find that negative number then divide by two and it will give u |vi| make it positive vf =0 at the top, so 0^2=vi^2 + 2a ∆x then -(vi^2)/(2a){should be 19.6}= ∆x
vf-vi=at, so find that negative number then divide by two and it will give u |vi| make it positive vf =0 at the top, so 0^2=vi^2 + 2a ∆x then -(vi^2)/(2a){should be 19.6}= ∆x
vf-vi=at, so find that negative number then divide by two and it will give u |vi| make it positive vf =0 at the top, so 0^2=vi^2 + 2a ∆x then -(vi^2)/(2a){should be 19.6}= ∆x
