During a baseball game, a batter hits a high pop-up.

Question

If the ball remains in the air for 4.59 s, how high does it rise? The acceleration of gravity is 9.8 m/s2 .

Answer 1

vf-vi=at, so find that negative number then divide by two and it will give u |vi|
make it positive
vf =0 at the top, so
0^2=vi^2 + 2a ∆x
then
-(vi^2)/(2a){should be 19.6}= ∆x