Asked by Kayla
During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 4.11 s, how high does it rise?
Answers
Answered by
Anonymous
242
Answered by
some highschool kid ya kno
vf-vi=at, so find that negative number then divide by two and it will give u |vi|
make it positive
vf =0 at the top, so
0^2=vi^2 + 2a ∆x
then
-(vi^2)/(2a){should be 19.6}= ∆x
make it positive
vf =0 at the top, so
0^2=vi^2 + 2a ∆x
then
-(vi^2)/(2a){should be 19.6}= ∆x
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