Question
During a baseball game, a batter hits a high pop- up. If the ball remains in the air for 6.0s, how high does it rise? Hint: calculate the height using the second half of the trajectory
Answers
bobpursley
The hint makes it two easy. From what height does it require for something to fall in three seconds.
h=1/2 g t^2
h=1/2 g t^2
Tatianna
176.4m
some highschool kid ya kno
maybe this help?
vf-vi=at, so find that negative number then divide by two and it will give u |vi|
make it positive
vf =0 at the top, so
0^2=vi^2 + 2a ∆x
then
-(vi^2)/(2a){should be 19.6}= ∆x
vf-vi=at, so find that negative number then divide by two and it will give u |vi|
make it positive
vf =0 at the top, so
0^2=vi^2 + 2a ∆x
then
-(vi^2)/(2a){should be 19.6}= ∆x