Asked by Isabella

During a baseball game, a batter hits a high pop- up. If the ball remains in the air for 6.0s, how high does it rise? Hint: calculate the height using the second half of the trajectory

Answers

Answered by bobpursley
The hint makes it two easy. From what height does it require for something to fall in three seconds.

h=1/2 g t^2
Answered by Tatianna
176.4m
maybe this help?

vf-vi=at, so find that negative number then divide by two and it will give u |vi|
make it positive
vf =0 at the top, so
0^2=vi^2 + 2a ∆x
then
-(vi^2)/(2a){should be 19.6}= ∆x
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions