exactly

This page lists questions and answers that were posted by visitors named exactly.

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The following questions were asked by visitors named exactly.

Answers

The following answers were posted by visitors named exactly.

Hmmm... hint: You analyse the degree then you're done.

This is a brilliant qn so i will only give you a hint: Use the law of sines.

Only a hint: do a case by case analysis. You need N observation tho

Hint: recurrence --> fibonacci. This question is reposted from brilliant.

Step 1; Factor f(x) = (x - r_1)...(x - r_1000) Step 2: Hint hint: something about roots and circle centered at r_i of radius 2 |r_i|^3 Step 3: triangle inequality --> implication: same argument. Step 4: Verify This is a brilliant question, therefore i wil...

If I am not wrong, the answer is 9.09E-9

Elaboration on drwl's answer: since p∼ρv^2 via Bernoulli's equation

brilliant qn again! Hint: consecutive

brilliant qn (as usual) Hint: I=ceN/L

hint: consecutive. This is a brilliant question please do not give full answer.

brilliant qn don't give any answer... Hint: fibonacci

Brilliant qn! hint for you : use recursion

I suppose this question isn't live anymore. Anyways next time please don't post brilliant problems (: Well, here's a few hints for you to work out and be on the right track: Step 1: quadratic reciprocity and CRT Step 2: incorporate dirichlet's theorem int...

Ok to clarify, the show that 2 and 3 must be quadratic residues part is to find the minimal.

Hint: you need these: (1) a,b,c,d are non-negative integers (2) 7−a−b≥0⇔a+b≤7 (3) 7−c−d≥0⇔c+d≤7 (4) 7−a−c≥0⇔a+c≤7 (5) 7−b−d≥0⇔b+d≤7 (6) a+b+c+d−7≥0⇔a+b+c+d≥7 Try to count how many satisfies these conditions (:

Alestair no point posting wrong answers. Anyways stop posting brilliant problems. Anyways since the live period is over, here is a hint: show that for a fixed n the number of polynomials is the number of divisors of n.

brilliant qn as usual. Since the live period is over, here is a hint: We only ned to consider irreducibles of degree≤1000 and consider how many ways there are to multiply such polynomials together to obtain a polynomial of degree 1000. Next show that |å|...

Well, I sort of get a different answer: ∠CMD = 45 Here's how I got it: Let CD = x. It is trivial by law of cosine that: BD = x√3 Whence DM = (√3 + 1)/2 * x. Let us denote the midpoint of BD as K. Then it is easy to see that: MK = DM - DK = x/2. Now it is...

Lets assume a charge of q is placed at a point (x,o) where 0<x<3. Your net force on that middle charge will be the sum of two electrostatic forces. Your plan is to use a distance of x for the force calculation between the leftmost charges and a distance o...

Well, apparently I have a different answer. Supposedly the live period is long over so I guess it is safe to discuss. Meanwhile, in the future, refrain from posting brilliant problems. Step 1: F_g = (m_w + m_g)* g Step 2: m_w = 𝜌 * V_m Step 3: For step 2,...

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