Stevium

This page lists questions and answers that were posted by visitors named Stevium.

Questions

The following questions were asked by visitors named Stevium.

How can a blackhole be stabilized by adding to its angular momentum

Can a massless body undergo repulsion

can an atom exist without a nucleus

Is it a must that a nucleus must have opposite nature with the electron

Tan theta +2sec theta=2 cot theta+3cosec theta=a Find theta

Answers

The following answers were posted by visitors named Stevium.

max, mark is 90,50 % is 45,he got 50 %,he got 45,if 3=1 que,45=15que,he got 15 que,there are 30ques,so 30-15=15,ans=15Q

Let X= multichoiceques,and Y=openQUES,(simulta,eqn) 4X+12Y=100,X+Y=15,then get your ans

what occurs when the atom has no nucleus

represent this: let a be 3/7b and let b be b,since they share the money: b+3/7b=420,then find b,and a(a=3/7b)

profit percent=13.33,S.P=17000, CP= 1x+0.1333x=17000,then CP=15000.44,Since the goods are sold at 85% Labelled price

Then labelled price=15000/0.85=17647.5. if no discount is given find the profit or loss % when it is sold at Rs17000

let x be price : x(1-0.22)=30,find x

Percentage increase: (81-75)/75*100=8%

Let us divide the ques into 3 parts: the initial v,the 20s descent,the final v,since distance from ground level=3000m.

Let us divide the ques into 3 parts: the initial v,the 20s descent,the final v,since distance from ground level=3000m,

the 1st part:using V=6 v*v/2g=h,36/20=1.8m,new distance(diver) from ground=3000+1.8=3001.8m.

2nd part:20s descent. using a=v-u/t,where a=10.t=20,and u=0,v=200,using v*v/2g=h,200*200/20=2000new h=3001.8-2000

Since final h=1001.8m,find the time,t=h/v, 1001.8/5m/s=200.36.total time=200.36+20+0.6=220.96get 0.6 from h=1.8

speed of sound=330m/s,there is unequal distance covered by the sound bcs the car was moving,then we should assume

Cont.d: -there is different time,let us use 4&2,4s for sound to go & 2s to come back,using : V=2D/T,find d using 4&2s.

Cont.d: in 4s we get 660m,& 2s,330m,therefore the speed of the car: D1-D2/T1-T2,where d1=large distance,t1=samE

You can try it with 5 and 1 second,you would get the same velocity

let no of class=x,boys & girls are equal,boys=1/2x, 5/6*1/2x are honoured ,then 1-5/6=1/6 are not= x(1 - 5/12)=1/12x

Let raj age be x,since ratio is 1:3,ram is 3x. after 5yrs: 3x+5=2+2(x+5), find x,and their respective ages

The question led me to a quadratic equation: let 1st nos be n,and 2nd be n+1 3/n+1 - 1/n=3/10,collect lcm:

3n-1(n+1)/n(n+1)=3/10. 10(2n-1)=3(n*n)+3n,20n-10=3(n*n)+3n,take like terms,find n,choose the integer as n's value.

64+9(12/3 * 2)-7,using bodmas within the brackets,division before multiplication=64+9(4*2)-7 64+9(8)-7=64+72-7=129

I think only one number can do: 123. 1+2+3=1*2*3=6

dis is inverse proportion: let w be no of days,find constant k : 18=K/35,K=630, 28=630/w,find your w

Find the kinetic energy of the arm,then equate it to work done,find the force using MV/T,then find your D,since W=F*D

the highest profit to be attained is 0,making it a quadratic equation,find x,any value not x gives a loss(-P)

Let x be unknown cup of flour.this is a direct proportion: 2.5 dozens/(15/8)=K,K=30/(15/8)=16,1/3 dozens/X=16,Find x

5,3 and 2 respectively

Let u be speed,C.U=0.5 ,M=5g(0.05Kg),Y=8Kg,since the 8Kg block is static : Mv=(M+Y)C.U,Solve for v

speed=15km/hR(15*1000)/3600=4.167m/s, h of pipe=f(t),where f(t)=4.167t,to solve,vol of pipe=voL of tank,

LBH=22/7*R"2*4.167T(h) . From here t= LBH/(Pi*r*4.167) t= 50*44*0.21(in m)/(pi* (0.07)"2*4.167)=7202.3 seconds

R=net force, And net force =mg-ma,m(g-a). R=499,m=691/9.8=70.51kg 499=70.51(9.8-a),find a,and a is directed upward

I think it's becos it's a formation reaction enthalpy is always: -deltaH:-1*-65.5=65.5KJ

No of girls=(1-2/9)x=7/9x. therefore 7/9x= (2/9)x+75,Collect like terms:7/9x-2/9x=75,finish the process and find x

2 is the required outcome,and the possible outcome=(0.52*5), Hence ; P(O)= 2/(0.52*5)=0.77

Find the relation between x&y,y&z,then x&z, x=9/2,when y=16/3,then (32/27)x=y,also y=25/4,when z=17/2,then z=(34/25)y,

Therefore z= (34/25)*(32/27)x=(1088/675)x.Hence x:y:z= x:(32/27)x:(1088/675)x,dividng through by x,you get x:y:z

Note your ans should be: 675:800:1088=x:y:z,when you multiply through by 675