A 5g bullet is fired horizontally and hits an 8kg block of wood (initially at rest) which can move freely. The wood and the bullet move with a velocity of 0.50 m/s after impact. What is the initial velocity of the bullet?
3 answers
Let u be speed,C.U=0.5 ,M=5g(0.05Kg),Y=8Kg,since the 8Kg block is static : Mv=(M+Y)C.U,Solve for v
conserve momentum:
5v = (8000+5)*0.50
5v = (8000+5)*0.50
Please help me