Ke$ha

This page lists questions and answers that were posted by visitors named Ke$ha.

Questions

The following questions were asked by visitors named Ke$ha.

in which sentence is the underlined infinitive or infinitive phrase function as a direct object? c. After all that exercise, the runners needed *to drink water*. d.Just as the mayor was about *to give an award*, it began raining. I would say its d?

Will someone please check if I am right???? find the second and third term of the arithmetic sequence -7, __,__,-22,-27... Options: -12,-15*** My Answer -17,-12 -10,-17 -12,-17

The deposits Ginny makes at her bank each month form an arithmetic sequence. The deposit for month 3 is $150, and the deposit for month 5 is $180. Answer these questions 1.what is common differences for each month? $15 2.write explicit formula for arithme...

Describe an infinite geometric series with a beginning value of 2 that converges to 10. What are the first four terms of the sequence? a{1} = first term of series ∞ Infinite Sum = ∑ a{1} • r^(n – 1) = a{1} ⁄ (1 – r) ... for any geometric series n =1 Infin...

FIND THE LIMIT!!! lim x--->3 sqrt(2x+3)- sqrt (3x)/(x^2-3x) I keep getting zero is this right?

I have no clue how to do this problem: lim---->2 then thees this little dash slightly above the 2 and then its |x-2|/(x-2)

HELP DERIVATIVES!!!!!!!!!!!!! if h(x)=f[f(x)] use the tables for f and f' to find the value of h'(1) X f(x) f'(x) 1 3 2 2 1 5 3 6 7

Help!!! determine the slope of the graph x^2=ln(xy) at point (1,e)

A particle is moving along the x-axis so that its position at t>=0 is given by s(t)=(t)ln(5t). Find the acceleration of the particle when the velocity is first zero.

find the volume of the solid formed by revolving the region bounded by the graphs of y=x^3 y=1 x=2 about the y-axis

find the area of the region bounded by the graphs of y=x^2 and y=cos(x)

For an object whose velocity in ft/sec is given by v(t) = −2t^2 + 4, what is its distance travelled, in feet, on the interval t = 0 to t = 2 secs? I think the answer is 2.667 but I am not one hundred percent sure.

Which of the following integrals will find the volume of the solid that is formed when the region bounded by the graphs of y = ex, x = 1, and y = 1 is revolved around the line y = -2

The base of a solid in the xy-plane is the first-quadrant region bounded y = x and y = x^2. Cross sections of the solid perpendicular to the x-axis are equilateral triangles. What is the volume, in cubic units, of the solid? So I got 1/30 because (integra...

Determine if the Mean Value Theorem for Integrals applies to the function f(x) = x^3 - 9x on the interval [-1, 1]. If so, find the x-coordinates of the point(s) guaranteed to exist by the theorem. I think one point is zero.

solve the differential equation dy/dx=y^2/x^3 for y=f(x) with condition y(1)=1.

f is a continuous function with a domain [−3, 9] such that f of x equals 3 for x between negative 3 and 0 including negative 3, equals negative 1 times x plus 3 for x between 0 and 6 inclusive, and equals negative 3 for x greater than 6 and less than or e...

Which of the following functions grows the fastest as x grows without bound? f(x)=x^2 g(x)=x^2+5x <<<<MY ANSWER h(x)=(sqrt x^4+2x) They all grow at the same rate Compare the growth rate of the functions f(x)=4^x and g(x)=(sqrt 16^x+2^x) f(x) grows faster...

f is a function that is differentiable for all reals. The value of f ′(x) is given for several values of x in the table below. The table: x -8,-3,0,3,8 f'(x)-4,-2,0,4,5 If f ′(x) is always increasing, which statement about f(x) must be true? f(x) passes t...

Use the graph of f(t) = 2t +2 on the interval [−1, 4] to write the function F(x), where f(x)= integral from 1 to x f(t) dt f(x)=x^2+3x f(x)=x^2+2x-12 My Answer f(x)x^2+2x-3 f(x)=x^2+4x-8 Find the range of the function f(x)=integral from 0 to x (sqrt 4-t^2...

the velocity of a particle moving along the x axis is v(t)=t^2+2t+1, with t measured in minutes and v(t) measured in feet per minute to the nearest foot find the total distance traveled by the particle from t=0 to t=2 minutes so, I took the integral of th...

find d/dx (integral from 2 to x^4) tan(x^2) dx tan(x^4)^2*4x^3 MY ANSWER

find the area bounded by the curves y^2=2x+6 and x=y+1

Write the integral in one variable to find the volume of the solid obtained by rotating the first‐quadrant region bounded by y = 0.5x2 and y = x about the line x = 5.

write n with limit from 0 to infinity with the summation n on top and k=1 on the bottom (5+k(2/n))^10 (2/n) as a definite integral.

Use the midpoint rule with n=4 to approximate the region bounded by y=-x^3 and y=-x Show that the function f(x)= (integral from 2x to 5x) (1)/(t) dt is constant on the interval (0,+infinity)

Answers

The following answers were posted by visitors named Ke$ha.

wait, wouldn't it be c because the verb needed ends in ed?

What were the answers??????

105+15n 285 month 27 these are my other answers

is this right???

You posted an entire test on here and expect people to do it for you?! Do your own tests!!!!!!!!!!!

THANK YOU!!!!!!!!!!!

f(x)=3,1,6 f'(x)=2,5,7 Just in case u cant read the chart

Thank you!!!!!!!

what is the difference between the two?

ok THANK YOU!!!!!!!

so the answer is none?

Yes I read it I still don't get it and 0 isn't an answer choice.

wait its 3 right?

oh ok thank you!!!! sorry

r = 4 in. h = 12 in. V = pi*r^2 * h = 3.14*4^2 * 12 = 602.88 m^3. r = 4.2 in. h = 12.2 in. V = 3.14*4.2^2 * 12.2 = 675.75 in^3 675.75-602.88 =72.87 in^3? is that right?

So my updated answer would be that the possible error is the volume of the cylinder is 63.87 in^3?

So the answer would be 1.0947?

I know it is pi (integral from zero to 1)then I get confused

for the second integral i got (sqrt 3)/60 how did you get (sqrt 3)/120?

Oh thank you!!!

Well that was my issue with the second one is I originally got that answer but it isn't an option.

Ok, so exactly how would I find the amount of water? I am confused now.

I am confused on how to do this. Will you please help?

So the total would be 1353.333 feet?

so we would get 9.05584?

yes! thank you!

For the first one i think the integral is from -1 to 1 for the two functions, because they intersect at (-1,1) (0,0) and (1,-1)

(-1,-1), (0,0) and (1,1). The four midpoints are -3/4, -1/4, +1/4, and +3/4. Each vertical strip has a width of 1/2. The lengths of the 4 strips are: -27/64-(-3/4); -1/64-(-1/4); 1/4 - 1/64; and 3/4-27/64; simplifying these, you get 21/64, 15/64, 15/64, a...