Asked by Someone
The end behavior of f(x)=(2+x^2)/(x^2-36) most closely matches which of the following:
y=1
y=-1
y=2
y=0
There is no leading coefficient so I am not sure what the answer is.
y=1
y=-1
y=2
y=0
There is no leading coefficient so I am not sure what the answer is.
Answers
Answered by
Someone
CORRECTION: THE SECOND OPTION IS NOT Y=-1 it is Y=-18
Answered by
Someone
The end behavior of f(x)=(2+x^2)/(x^2-36) most closely matches which of the following:
y=1
y=-18
y=2
y=0
y=1
y=-18
y=2
y=0
Answered by
Steve
as x gets huge, the 2 and the 36 become insignificant:
y -> x^2/x^2
y -> x^2/x^2
Answered by
Someone
so the answer is 2?
Answered by
Steve
since when is x^2/x^2 = 2?
10/10 = 1
z^3/z^3 = 1
don't forget your Algebra I now that you're taking calculus.
Using the usual method, divide top and bottom by x^2. That gives you
(1 + 2/x^2)/(1 - 36/x^2)
as x^2 gets huge, 1/x^2 -> 0
and the fraction becomes 1/1
NOT 2!!
10/10 = 1
z^3/z^3 = 1
don't forget your Algebra I now that you're taking calculus.
Using the usual method, divide top and bottom by x^2. That gives you
(1 + 2/x^2)/(1 - 36/x^2)
as x^2 gets huge, 1/x^2 -> 0
and the fraction becomes 1/1
NOT 2!!
Answered by
Ke$ha
ok THANK YOU!!!!!!!