Asked by Spring Allergies
What is the end behavior of the graph of f(x) = -0.25x^2 - 2x + 1?
A) As x increases, f(x) increases. As x decreases, f(x) decreases. ***
B) As x increases, f(x) decreases. As x decreases, f(x) decreases.
C) As x increases, f(x) increases. As x decreases, f(x) increases.
D) As x increases, f(x) decreases. As x decreases, f(x) increases.
I'm not very good at math so if someone could help me
A) As x increases, f(x) increases. As x decreases, f(x) decreases. ***
B) As x increases, f(x) decreases. As x decreases, f(x) decreases.
C) As x increases, f(x) increases. As x decreases, f(x) increases.
D) As x increases, f(x) decreases. As x decreases, f(x) increases.
I'm not very good at math so if someone could help me
Answers
Answered by
CodyJinks
Go the website called Desmos and input your graph so you can see the behavior. I think you might change your mind
Answered by
Spring Allergies
Thank you so much! It did help!
Answered by
henry2,
F(x) = -0.25x^2 - 2x + 1.
F(0) = -0.25*0^2 - 2*0 + 1 = 0 + 0 +1 = 1.
F(1) = -0.25*1^2 - 2*1 + 1 = -0.25 - 2 + 1 = -1.25. decreased.
F(2) =
F(0) = -0.25*0^2 - 2*0 + 1 = 0 + 0 +1 = 1.
F(1) = -0.25*1^2 - 2*1 + 1 = -0.25 - 2 + 1 = -1.25. decreased.
F(2) =
There are no AI answers yet. The ability to request AI answers is coming soon!