Asked by Ke$ha
write n with limit from 0 to infinity with the summation n on top and k=1 on the bottom (5+k(2/n))^10 (2/n) as a definite integral.
Answers
Answered by
Steve
You want the integral to be something of the form
∫[a,b] f(x) dx
Now that (2/n) at the end indicates that we are dividing 2 into n parts, so we will have
∫[0,2] f(x) dx
Now we see that k*2/n inside the sum, so that is the value of x at each of the interval divisions, so I expect it to be
∫[0,2] (5+2x)^10 dx
∫[a,b] f(x) dx
Now that (2/n) at the end indicates that we are dividing 2 into n parts, so we will have
∫[0,2] f(x) dx
Now we see that k*2/n inside the sum, so that is the value of x at each of the interval divisions, so I expect it to be
∫[0,2] (5+2x)^10 dx
Answered by
Ke$ha
Thank you!
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