write n with limit from 0 to infinity with the summation n on top and k=1 on the bottom (5+k(2/n))^10 (2/n) as a definite integral.

Answer 1

You want the integral to be something of the form
∫[a,b] f(x) dx

Now that (2/n) at the end indicates that we are dividing 2 into n parts, so we will have

∫[0,2] f(x) dx

Now we see that k*2/n inside the sum, so that is the value of x at each of the interval divisions, so I expect it to be

∫[0,2] (5+2x)^10 dx

Answer 2

Thank you!