FIND THE LIMIT!!! lim x--->3

Question

sqrt(2x+3)- sqrt (3x)/(x^2-3x)
I keep getting zero is this right?

Answer 1

(√(2x+3)-√(3x))/(x^2-3x)

If you have l'Hospital's Rule as a tool, then you know that the limit is the same as

(1/√(2x+3) - 3/(2√(3x)) / (2x-3)
= (1/3 - 3/6)/3
= -1/18