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Find the limit of (10^x - 5^x)/x as x approaches 0

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Using L'Hopital's rule

limit (10^x - 5^x)/x as x ---> 0
= limit ln10(10^x) - ln5(5^x) as x -->0
= ln10(1) - ln5(1)
= ln 10/5
= ln 2
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