Asked by kat

find the limit for the given function

lim (sin)^2(3 t))/t^2
t->0

Answers

Answered by drwls
Remember and apply L'Hopital's rule. (Take the ratio of the derivatives of numerator and denominator). You may have to use it twice.

OR use the fact that sin x approaches x as x-> 0.
(sin)^2(3 t))/t^2 therefore approaches
(3t)^2/t^2 = 9
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