Asked by kat
find the limit for the given function
lim (sin)^2(3 t))/t^2
t->0
lim (sin)^2(3 t))/t^2
t->0
Answers
Answered by
drwls
Remember and apply L'Hopital's rule. (Take the ratio of the derivatives of numerator and denominator). You may have to use it twice.
OR use the fact that sin x approaches x as x-> 0.
(sin)^2(3 t))/t^2 therefore approaches
(3t)^2/t^2 = 9
OR use the fact that sin x approaches x as x-> 0.
(sin)^2(3 t))/t^2 therefore approaches
(3t)^2/t^2 = 9
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