JUNDY

This page lists questions and answers that were posted by visitors named JUNDY.

Questions

The following questions were asked by visitors named JUNDY.

A weighed amount of sodium chloride is completely dissolved in a measured volume of 4.00 M ammonia solution at ice temperature, and carbon dioxide is bubbled in. Assume that sodium bicarbonate is formed until the limiting reagent is entirely used up. The...

The autodissociation of water to H+ and OH- is endothermic. At a higher temperature more of the water molecules have sufficient energy to dissociate. So, Kw is greater. At 25oC, Kw = 1.0 x 10-14. (standard Kw) At 65oC, Kw = 1.0 x 10-13. Calculate the hydr...

Calculate the hydrogen ion concentration, [H+], in 0.00988 M Ba(OH)2. Careful!

1)A buffer solution that is 0.10 M sodium acetate and 0.20 M acetic acid is prepared. Calculate the initial pH of this solution. The Ka for CH3COOH is 1.8 x 10-5 M. As usual, report pH to 2 decimal places. *A buffered solution resists a change in pH.* 2)C...

Concentrated hydrochloric acid is 38% HCl by weight and has a density of 1.19 g/mL. A solution is prepared by measuring 70 mL of the concentrated HCl, adding it to water, and diluting to 0.500 L. Calculate the approximate molarity of this solution from th...

A reaction at 2.43 atm produces 20.0 L of a gas and evolves 75.3 kJ of heat (exothermic). Calculate the change in internal energy of the system (in kJ).

A reaction at 3.24 atm consumes 5.10 L of a gas adiabatically (q = 0). Calculate the change in internal energy of the system (in kJ).

1.578 g of an unknown hydrocarbon (110.7 g/mol) burns in bomb calorimeter in excess oxygen. The heat capacity of the calorimeter,Cv, = 5.709 kJ/ºC and ΔT =7.995 ºC. Find ΔE for this hydrocarbon in kJ/mol.

A reaction at 3.24 atm consumes 5.10 L of a gas adiabatically (q = 0). Calculate the change in internal energy of the system (in kJ). I know that I have to use w=-p deltaV but how do i find the Final and Initial volumes?

Calculate ΔG (in kJ) at 298 K for some solid ZnF2, 0.055 M Zn2+ and 0.063 M F-(aq). I found Q to be 2.18e-4, then i implemented it into the equation deltaG=RT(lnQ). I got -20.89, but the answer is -12.2.

Calculate the vapor pressure of Hg at 14 oC (in atm). Hg(l) ↔ Hg(g) . . . ΔHo = 61.32 kJ and ΔSo = 98.83 J/K

What is the oxidation state assigned to Cr in zinc dichromate, ZnCr2O7?

A half-cell that consists of a copper wire in 1.00 M CuNO3 solution is connected by a salt bridge to a half cell containing a 1.00 M X(II) acetate solution and an electrode of metal X. The voltage of the cell is 2.00 V, with metal X as the positive electr...

Calculate ΔGo (in J) for 2 moles of electron(s) in each half-reaction and a standard potential of 0.57 V.

A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the solution is taken out and is titrated to a neutral endpoint with 0.10 M NaOH. The titrated portion is then mixed with the remaining untitrated portion and th...

There are three isotopes of phosphorus. Only one of them is stable. Calculate the binding energy per nucleon (in MeV) for P-32 (atomic mass = 31.9739 u). mass H = 1.007825 u and mass n = 1.008665 u. I multiplied the protons(15) by the mass H, and the neut...

Answers

The following answers were posted by visitors named JUNDY.

Find the moles of ethanol and the moles of the solution, and divide ethanol by the solution.

Ill post my work

Actually can you help me find the pH at the equilibrium point, my work: HOCl OH- I .004 .004 C -.004 -.004 E 0 0 .01*.400=.004 .008*.5=.004 I don't know what to do next...

Just multiply all three dimensions to get you volume.

a. 3/4 b. 4/8 c. 1/4 d. 2/7

M1V1 = M2V2 (.125L)(10.30M)=(x)(.500M)

Don't Include Oxygen in your equation and try it again.

In an arithmetic series, every term is separated from its neighbours by the same difference. So given an arithmetic sequence that starts with the first value A and has a common difference of D, the first five terms are: 1st term: A 2nd term: A + D 3rd ter...

It's a limiting reagent problem. 8mol*(64.07 g/mol)=512.56 g 16mol*(34.07 g/mol)=545.12 g Therefore, SO2 is the limiting reagent. Figure out the rest

Yes, that's correct.