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M1V1 = M2V2
(.125L)(10.30M)=(x)(.500M)
(.125L)(10.30M)=(x)(.500M)
CāVā = CāVā
Where:
Cā = initial concentration of the stock solution (in M)
Vā = initial volume of the stock solution (in mL)
Cā = final concentration desired (in M)
Vā = final volume desired (in mL)
Given:
Cā = 10.30 M
Vā = 125 mL
Cā = 0.500 M
Let's plug these values into the dilution equation and solve for Vā, which represents the final volume:
(10.30 M)(125 mL) = (0.500 M)(Vā)
Now, we can solve for Vā:
Vā = (10.30 M)(125 mL) / 0.500 M
Vā = (10.30 M * 125 mL) / 0.500 M
Vā = (1287.5 mL * M) / M
Vā = 1287.5 mL
Therefore, the final volume required to dilute 125 mL of a 10.30 M nitric acid stock solution to 0.500 M is 1287.5 mL.