What is the final volume if 125 mL of a stock solution of nitric acid at 10.30 M is diluted to 0.500 M?

M1V1 = M2V2

(.125L)(10.30M)=(x)(.500M)

2.57

To calculate the final volume when diluting a solution, you can use the dilution equation:

C₁V₁ = C₂V₂

Where:
C₁ = initial concentration of the stock solution (in M)
V₁ = initial volume of the stock solution (in mL)
C₂ = final concentration desired (in M)
V₂ = final volume desired (in mL)

Given:
C₁ = 10.30 M
V₁ = 125 mL
C₂ = 0.500 M

Let's plug these values into the dilution equation and solve for V₂, which represents the final volume:

(10.30 M)(125 mL) = (0.500 M)(V₂)

Now, we can solve for V₂:

V₂ = (10.30 M)(125 mL) / 0.500 M

V₂ = (10.30 M * 125 mL) / 0.500 M

V₂ = (1287.5 mL * M) / M

V₂ = 1287.5 mL

Therefore, the final volume required to dilute 125 mL of a 10.30 M nitric acid stock solution to 0.500 M is 1287.5 mL.