Asked by JUNDY
Calculate ΔG (in kJ) at 298 K for some solid ZnF2, 0.055 M Zn2+ and 0.063 M F-(aq).
I found Q to be 2.18e-4, then i implemented it into the equation deltaG=RT(lnQ). I got -20.89, but the answer is -12.2.
I found Q to be 2.18e-4, then i implemented it into the equation deltaG=RT(lnQ). I got -20.89, but the answer is -12.2.
Answers
Answered by
DrBob222
I think the formula is
dG = -RTlnK but that won't get -12.2. It changes the sign of the number you obtained from - to +.
dG = -RTlnK but that won't get -12.2. It changes the sign of the number you obtained from - to +.
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