Asked by JUNDY
The autodissociation of water to H+ and OH- is endothermic. At a higher temperature more of the water molecules have sufficient energy to dissociate. So, Kw is greater.
At 25oC, Kw = 1.0 x 10-14. (standard Kw)
At 65oC, Kw = 1.0 x 10-13.
Calculate the hydrogen ion concentration, [H+], in 0.0474 M LiOH at 65oC.
At 25oC, Kw = 1.0 x 10-14. (standard Kw)
At 65oC, Kw = 1.0 x 10-13.
Calculate the hydrogen ion concentration, [H+], in 0.0474 M LiOH at 65oC.
Answers
Answered by
DrBob222
LiOH = 0.0474M
(OH^-) = 0.0474M
(H^+)(OH^-) = 1E-13
Substitute the OH^- from LiOH and solve for H^+.
(OH^-) = 0.0474M
(H^+)(OH^-) = 1E-13
Substitute the OH^- from LiOH and solve for H^+.
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