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Henry.
Answers (19)
Vs = 142,000m/3600s = 39.44 m/s. 3600s = 1 hour. 142km = 142,000 m.
Y = x^2 + 2x. Y = 3x + 20. In Eq1, replace Y with 3x + 20: 3x + 20 = x^2 + 2x, x^2 + 2x - 3x -20 = 0, x^2 - x - 20 = 0. Solve the Eq by factoring.
1.x^2 - 6x + 9 = 0. Solve the Eq. by factoring: 9 = -3 * -3. (x-3) (x-3) = 0, x-3 = 0, X = 3. 3 should satisfy both of your given Eqs.
Y = 4x + 8. Y = x^2 + 7x - 20. In Eq2, replace Y with 4x + 8: 4x + 2 = x^2 + 7x - 20. x^2 + 3x - 22 = 0. Solve using Quadratic Formula: X = (-B +- sqrt(B^2-4AC))/2A. X = (-3 +- sqrt(9 + 88))/2 = 3.42, and -6.42.
Y = x^2 + 9. Y = 6x. In Eq1, replace Y with 6x: 6x = x^2 + 9. x^2 - 6x + 9 = 0. Solve the Quadratic Eq .
a. B^2-4AC = 36-(-84) = 120. The discriminant is positive. Therefore, we have 2 real solutions. b. B^2-4AC = 324-324 = 0. 1 real solution.
a. V = Vo + g*t. 0 = 184 - 32*t t = ? b. Use the given Eq. and the calculated value of t to find max. ht.
a. Fd = ((Vs+Vd)/(Vs-Vc)) * Fc. Fd = ((340+30)/(340-40)) * 820 = b. Fd = ((340-30)/(340+40)) * 820 = So the frequency heard by the driver will be greater than 820 Hz as the police car approaches but less than 820 Hz as the car passes the truck.
X parts planned for each team. 1st team produced 0.2x more than planned. 2nd team produced 0.15x more than planned. 0.2x + 0.15x = 118. X = 337.
Given: M1 = 2m, V 1 = 2v. M2 = m, V2 = 3v.[90o]. V3 = Velocity of M1 and M2 after collision. Momentum before = Momentum after: M1*V1 + M2*V2 = M1*V3 + M2*V3. 2m*2v + m*3vi = 2m*V3 + m*V3, Divide both sides by m: 4v + 3vi = 3V3, 3V3 = 5v[36.9o], V3 =
V = 200,000m/3600s = 55.6 m/s = Final velocity. V = Vo + a*t = 55.6 0 + a*3 = 55.6, a = 18.52 m/s^2. 18.52m/s^2/9.8m/s^2 = 1.89 Times acceleration due to gravity.
The STD form of a parabola that opens to the right. X = 2y^2 + 4y - 1.
75 + 0.15*225 = 108.75 grams of alcohol. %Alcohol = (108.75/(75+225)) * 100% = 36.25.
Sheets =(24 * 8 )/(8 * 4) = 6 .
Cost = (55/60) * 30 =
Stretch = 30-25 = 5 cm. Length = 25 + (200N/100N) * 5cm = 25 + 10 = 35 cm.
m = (-5-6)/(x-2) = -11/7. -11/(x-2) = -11/7, -77 = -11x + 22, 11x = 99, X = 9.
%Profit = ( (480-320)/320)*100% = 50%. Note: I'm assuming he did not get a refund for the cracked eggs.
Correction: M*g = 55 b* 9.8 = 539 N. = Wt. of load. Fn = 539 - 600*sin30 = 239 N. Fk = u*Fn = 0.3 * 239 = 71.7 N. = Force of kinetic friction. F*Cos30-Fk = M*a. 600*Cos30-71.7 = 55*a. a = ?
