How do I do these?

Solve the system of equations:

y=x^2 + 9
y=6x

Solve the system of equations:

y=4x+8
x^2 + 7x - 20

Y = x^2 + 9.

Y = 6x.
In Eq1, replace Y with 6x:
6x = x^2 + 9.
x^2 - 6x + 9 = 0.
Solve the Quadratic Eq .

So wait would x^2 - 6x + 9 = 0 be the answer for number 1?

Y = 4x + 8.

Y = x^2 + 7x - 20.
In Eq2, replace Y with 4x + 8:
4x + 2 = x^2 + 7x - 20.
x^2 + 3x - 22 = 0.
Solve using Quadratic Formula:
X = (-B +- sqrt(B^2-4AC))/2A.
X = (-3 +- sqrt(9 + 88))/2 = 3.42, and -6.42.

1.x^2 - 6x + 9 = 0.

Solve the Eq. by factoring:
9 = -3 * -3.
(x-3) (x-3) = 0,
x-3 = 0, X = 3.
3 should satisfy both of your given Eqs.

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