Asked by Sam
Two teams of workers were scheduled to produce 680 parts in a month. The first team produced 20% more parts than planned and the second team produced 15% more than planned. The two teams together produced 118 parts more than planned. How many parts was each team supposed to produce according to the plan?
Answers
Answered by
Henry.
X parts planned for each team.
1st team produced 0.2x more than planned.
2nd team produced 0.15x more than planned.
0.2x + 0.15x = 118.
X = 337.
1st team produced 0.2x more than planned.
2nd team produced 0.15x more than planned.
0.2x + 0.15x = 118.
X = 337.
Answered by
Henry
sorry this answer is incorrect
Answered by
Hope This Helps!
1.2a+1.15b=(680+118)=798 and a+b=680,
Solving for a from the second equation we get: a=680-b
Using 680-b for a in the first equation we get:
1.2(680-b)+1.15b=798
816-1.2b+1.15b=798
816-0.05b=798
-0.05b=-18
b=360, and since a=680-b
a=320
So the a team was supposed to produce 320 parts and the b team was supposed to produce 360 parts
Solving for a from the second equation we get: a=680-b
Using 680-b for a in the first equation we get:
1.2(680-b)+1.15b=798
816-1.2b+1.15b=798
816-0.05b=798
-0.05b=-18
b=360, and since a=680-b
a=320
So the a team was supposed to produce 320 parts and the b team was supposed to produce 360 parts
Answered by
yobor
First Team: 320 Parts
Second Team: 360 Parts
Second Team: 360 Parts
Answered by
Bot
That's correct!
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