Asked by Abishek
A 12000 kg airplane launched by a catapult from an aircraft carrier is accelerated from 0 to 200 km/h in 3 s. (a) How many times the acceleration due to gravity is the airplane's acceleration?
Answers
Answered by
scott
g = 9.8 m/s
a = 2E5 m / 1.08E4 s^2 = 19 m/s^2
looks like about 2
a = 2E5 m / 1.08E4 s^2 = 19 m/s^2
looks like about 2
Answered by
scott
g = 9.8 m/s^2
a = 2E5 m / 1.08E4 s^2 = 19 m/s^2
looks like about 2
a = 2E5 m / 1.08E4 s^2 = 19 m/s^2
looks like about 2
Answered by
Henry.
V = 200,000m/3600s = 55.6 m/s = Final velocity.
V = Vo + a*t = 55.6
0 + a*3 = 55.6,
a = 18.52 m/s^2.
18.52m/s^2/9.8m/s^2 = 1.89 Times acceleration due to gravity.
V = Vo + a*t = 55.6
0 + a*3 = 55.6,
a = 18.52 m/s^2.
18.52m/s^2/9.8m/s^2 = 1.89 Times acceleration due to gravity.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.