y = -14sin(8x)2cos(5x) - 4sin(5x)cos(8x)

y = -14sin(8x)2cos(5x) - 4sin(5x)cos(8x)u = -14sin(8x) u' = -112cos(8x) v = 2cos(5x) v' = -10sin(5x) u2 = -4sin(5x) u'2 =
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Multiply then use fundamental identities to simplify the expression below and determine which of the following is not equivalent
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y = 2[cos1/2(f1 - f2)x][cos1/2(f1 + f2)x]let f1 = 16 let f2 = 12 therefore y = 2[cos1/2(16 - 12)x][cos1/2(16 + 12)x] y =
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Solve 2cos^2(x) + 4sin(x)-3 = 0, giving all solutions in the interval 0 ≤ x ≤ 2π
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Solve the equation for solutions in the interval 0<=theta<2piProblem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1
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2. asked by Renee
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If f(x)=sin(2x), find f"(x)A. 2cos(2x) B. -4sin(2x) C. -2sin(2x) D. -4sinx E. None of these Is it B from using chain rules?
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3. 427 views
Solve the following Trigonometric equations, where 0 <= x <= 2πa) sin^2 θ-1 = 0 b) cos2θ=1 c) 4sin^2 θ-3 = 0 d) 2cos^3 - cos
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