Asked by Muneer
Solve the following Trigonometric equations, where 0 <= x <= 2π
a) sin^2 θ-1 = 0
b) cos2θ=1
c) 4sin^2 θ-3 = 0
d) 2cos^3 - cos θ = 0
e) 4cos^2 θ-4cosθ + 1 = 0
a) sin^2 θ-1 = 0
b) cos2θ=1
c) 4sin^2 θ-3 = 0
d) 2cos^3 - cos θ = 0
e) 4cos^2 θ-4cosθ + 1 = 0
Answers
Answered by
oobleck
C'mon - this is just Algebra I in disguise.
For example,
(e) is
(2cosθ - 1)^2 = 0
cosθ = 1/2
θ = π/3, 11π/3
Try the others, and come back with your work if you get stuck
For example,
(e) is
(2cosθ - 1)^2 = 0
cosθ = 1/2
θ = π/3, 11π/3
Try the others, and come back with your work if you get stuck