Asked by Randy
Prove the following trigonometric identity: (sec^2x-1)(csc^2x-1)=1
Answers
Answered by
chemistry
randy re check the question and use brackets to identify
do u mean secant squared?
or secant to the power of 2x-1
do u mean secant squared?
or secant to the power of 2x-1
Answered by
Randy
secant squared... ((sec^2)x-1)((csc^2)x-1)
Answered by
chemistry
re write the question properly
sec^2 x?
is there something there?
there should be either x or thetha there
and is it multplied
sec^2 x?
is there something there?
there should be either x or thetha there
and is it multplied
Answered by
Randy
Sorry forgot the =1 on the end, ((sec^2)x-1)((csc^2)x-1)=1
Answered by
helper
(sec^2 (x) - 1)(csc^2 (x) - 1) = 1
sec^2 (x) - 1 = tan^2 (x)
csc^2 (x) - 1 = cot^2 (x)
(tan^2 (x) )(cot^2 (x)) = 1
cot^2 (x) = 1/tan^2 (x)
(tan^2 (x) )(1/tan^2 (x))= 1
tan^2 (x)/tan^2 (x)= 1
1 = 1
sec^2 (x) - 1 = tan^2 (x)
csc^2 (x) - 1 = cot^2 (x)
(tan^2 (x) )(cot^2 (x)) = 1
cot^2 (x) = 1/tan^2 (x)
(tan^2 (x) )(1/tan^2 (x))= 1
tan^2 (x)/tan^2 (x)= 1
1 = 1
Answered by
Randy
Thank you.
Answered by
helper
you're welcome
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