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x= arccos(-√2/2) - cos(arcsin√5/3)
Please can you help me with this question?
Choose the option which is a false statement: A arctan(tan2/3pi))=-1/3pi B
1 answer
asked by
janet
606 views
Find the exact value of cot(arcsin(12/13))
and cos(arcsin(1.7/2)) I know that cos(arcsin(x))=sin(arccos(x))=sqrt(1-x^2). I'm
3 answers
asked by
Emily
1,150 views
Verify each identity.
a) arcsin(-x) = -arcsin x; abs. val. (x) is less than or equal to 1. b) arccos(-x) = pi - arccos x; abs.
0 answers
asked by
Erica
434 views
Use a calculator to evaluate the expression.
arcsin 0.45 arctan 15 arcsin(-0.125) arccos(-1/3)
1 answer
asked by
Jackie
1,033 views
Evaluate please:
a.) arcsin(sin 13pi/16) b.) arccos(cos[-pi/18]) c.) arcsin(sin pi/18 d.) arcsec(-√2) e.) arctan(-√3/3)
1 answer
asked by
Liv
1,043 views
Problem:
cos[arccos(-sqrt3/2)-arcsin(-1/2)] This is what I have: cos [(5pi/6)-(11pi/6)] cos (-6pi/6) or -pi giving an answer of
2 answers
asked by
Dennis
656 views
How do I do this by sketching a triangle.
sin( arcsin(1/2) + arccos(1/2) ) Thanks. let's start with arcsin(1/2) draw a right
0 answers
asked by
Jen
684 views
Write the trigonometric expression as an algebraic expression.
1.) SIN(ARCSIN X+ARCCOS X) ANSWER: 1 2.) SIN(ARCTAN 2X-ARCCOS X)
1 answer
asked by
AwesomeGuy
2,104 views
Book works out integral of sqtr(a^2-x^2)dx as a^2/2*arcsin(x/a)+x/2*sqrt(a^2-x^2) by taking x=a sin theta, and advises to work
2 answers
asked by
ms
665 views
x= arccos(-√2/2) - cos(arcsin√5/3)
1 answer
asked by
Anonymus
412 views