Asked by Dennis
Problem:
cos[arccos(-sqrt3/2)-arcsin(-1/2)]
This is what I have:
cos [(5pi/6)-(11pi/6)]
cos (-6pi/6) or -pi
giving an answer of -1
What I am wondering is should I use the (11pi/6) or should I use (-pi/6) because of the restrictions on arcsin x (-pi/2)<=x<=(pi/2)
Thank you in advance.
cos[arccos(-sqrt3/2)-arcsin(-1/2)]
This is what I have:
cos [(5pi/6)-(11pi/6)]
cos (-6pi/6) or -pi
giving an answer of -1
What I am wondering is should I use the (11pi/6) or should I use (-pi/6) because of the restrictions on arcsin x (-pi/2)<=x<=(pi/2)
Thank you in advance.
Answers
Answered by
bobpursley
I would use the smaller angle. It should not matter on the final answer.
Answered by
Dennis
Thank you very much.
The answer doesn't change, but my trig teacher wants to see all of work, and I just wasn't sure which figure to use.
The answer doesn't change, but my trig teacher wants to see all of work, and I just wasn't sure which figure to use.
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