let u = sin x so du/dx = cos x
y = cos^-1 (u)
dy/dx = - [1/(1-u^2)^.5 ] du/dx
= -[ 1/cos x] cos x
= -1
we agree
y=arccos(sin(x)), find dy/dx.
I got -1, is this correct? When I tried to check on wolfram alpha I didn't get this right.
2 answers
It should be plus and minus 1 though right?