Asked by Beth

y=arccos(sin(x)), find dy/dx.

I got -1, is this correct? When I tried to check on wolfram alpha I didn't get this right.
Answered by Damon
let u = sin x so du/dx = cos x

y = cos^-1 (u)

dy/dx = - [1/(1-u^2)^.5 ] du/dx

= -[ 1/cos x] cos x

= -1
we agree
Answered by Beth
It should be plus and minus 1 though right?
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