Question

y=arccos(sin(x)), find dy/dx.

I got -1, is this correct? When I tried to check on wolfram alpha I didn't get this right.

Answer 1

let u = sin x so du/dx = cos x

y = cos^-1 (u)

dy/dx = - [1/(1-u^2)^.5 ] du/dx

= -[ 1/cos x] cos x

= -1
we agree

Answer 2

It should be plus and minus 1 though right?