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solve csc^2x - cscx +
integral of cscx^(2/3)(cot^3)x
i know that cot^2x is csc^2(x)-1, but i just don't understand how to solve the cscx^(2/3), any
1 answer
asked by
Brandon
1,018 views
express in sinx
1 1 ---------- + -------- cscx + cotx cscx - cotx and express in cosx 1 + cot x ------- - sin^2x cscx = 1/sinx so
0 answers
asked by
linds
788 views
Find a numerical value of one trigonometric function of x if
tanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
1 answer
asked by
Lucy
978 views
Prove the following identity. Show all steps clearly. the ----- indicates that it is a fraction.
L.S cos2x sin(pi+x)
2 answers
asked by
Riley
674 views
solve for all possible x in [0,2pi):
(cscx+2)(cscx-√(2))=0
1 answer
asked by
Amanda
472 views
express this in sinx
(1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B) express in cosx problem: is 1 +
1 answer
asked by
linds
1,419 views
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity.
(x=theta BTW)
1 answer
asked by
Jon
651 views
verify (csc^4-1)/cot^2x=2+cot^2x
So this is what I have so far on the left side (csc^2x+1)(cscx+1)(cscx-1)/cot^2x
1 answer
asked by
Diana
753 views
hello
i know that deriv(cscx) = -cscxcotx and that deriv(cos) = -sinx deriv(cotx) = -((cscx)^2) my question is: is this
1 answer
asked by
CALLIE CALC
666 views
My previous question:
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
2 answers
asked by
Jon
941 views