solve (sq.rt 2) (tanx)(cosx) =

Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
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2. asked by Anonymous
3. 1,101 views
Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
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2. asked by Dave
3. 1,475 views
I have been trying to figure out these limit problems and I get stuck on trying to move the function around to make it possible
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2. asked by terra
3. 699 views
How do I solve this?tan^2x= 2tanxsinx My work so far: tan^2x - 2tanxsinx=0 tanx(tanx - 2sinx)=0 Then the solutions are: TanX=0
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2. asked by Chris
3. 3,824 views
1/tanx-secx+ 1/tanx+secx=-2tanxso this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
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2. asked by olivia
3. 1,361 views
Prove the following identity:1/tanx + tanx = 1/sinxcosx I can't seem to prove it. This is my work, I must've made a mistake
1. 1 answer
2. asked by Heather
3. 814 views
Proving identity(sinx+tanx)/(cosx+1)=tanx RS: (sinx+(sinx/cosx))/(cosx+1) ((sinxcosx/cosx)+(sinx/cosx))x 1/(cosx+1)
1. 1 answer
2. asked by sh
3. 643 views
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
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2. asked by Marrion
3. 709 views
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
1. 1 answer
2. asked by Marrion
3. 708 views
How do I solve: sqrt(3)tanx=I need to use the identity tanx=sinx/cosx Thanks
1. 2 answers
2. asked by Bob
3. 584 views