Ask a New Question
Search
log8-log4/log4-log2
log4(2*256x^4)
i know that log4(2)+log4(256)+log4(x^4) = log2^2(2)+4+4log4(x) but now I am stuck thanks
1 answer
asked by
Matilda
321 views
log8-log4/log4-log2
1 answer
asked by
Bola
174 views
Solve log4 x + log4(x-2)=log4(15)
I know how do the example in my book but I don't know what I'm doing wrong here. log4 x +
2 answers
asked by
Anonymous
1,768 views
Simply the following as far as possible.
1.log8 - log4*log6/log4 2.log8+log4
1 answer
asked by
Sheik sudani Al Qatar La muktal.
443 views
Which of the following options rewrites log4(9m3n) using the Quotient Rule of Logarithms, the Product Rule of Logarithms, and
1 answer
asked by
anonymous tortel
121 views
1. Given log2(m) = x, log4(n) = y
What is mn? 2. Given log5(m) = x, log√5(n) = y What is mn? 3. Given log2(m^2) = x, log8(√n)
2 answers
asked by
a
1,083 views
Simplify log8-log3/log4-log2
1 answer
asked by
Princess
135 views
Which of the following options rewrites log4(9m3n) using the Quotient Rule of Logarithms, the Product Rule of Logarithms, and
1 answer
asked by
hi
130 views
Simplify:
1. 2log10^5+log10^4 2. 2log3^6-log3^4 3. log4^40-log4^5 4. log4^3-log4^48 I need to see all of the steps. Thanks
1 answer
asked by
Brandon
774 views
Solve, round to four decimal places if necessary:
log4(x-9)=2 Answer: x-9=4^2 x-9=16 x=11 log4(z)+log4(z-3)=1 Answer: z+z-3=1
2 answers
asked by
Lucy
831 views