log8-log4/log4-log2

  1. log4(2*256x^4)i know that log4(2)+log4(256)+log4(x^4) = log2^2(2)+4+4log4(x) but now I am stuck thanks
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    2. Matilda asked by Matilda
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  2. log8-log4/log4-log2
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    2. Bola asked by Bola
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  3. Solve log4 x + log4(x-2)=log4(15)I know how do the example in my book but I don't know what I'm doing wrong here. log4 x +
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    2. Anonymous asked by Anonymous
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  4. Simply the following as far as possible.1.log8 - log4*log6/log4 2.log8+log4
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    2. Sheik sudani Al Qatar La muktal. asked by Sheik sudani Al Qatar La muktal.
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  5. Which of the following options rewrites log4(9m3n) using the Quotient Rule of Logarithms, the Product Rule of Logarithms, and
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    2. anonymous tortel asked by anonymous tortel
    3. views icon 128 views
  6. 1. Given log2(m) = x, log4(n) = yWhat is mn? 2. Given log5(m) = x, log√5(n) = y What is mn? 3. Given log2(m^2) = x, log8(√n)
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    2. a asked by a
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  7. Simplify log8-log3/log4-log2
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    2. Princess asked by Princess
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  8. Which of the following options rewrites log4(9m3n) using the Quotient Rule of Logarithms, the Product Rule of Logarithms, and
    1. answers icon 1 answer
    2. hi asked by hi
    3. views icon 139 views
  9. Simplify:1. 2log10^5+log10^4 2. 2log3^6-log3^4 3. log4^40-log4^5 4. log4^3-log4^48 I need to see all of the steps. Thanks
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    2. Brandon asked by Brandon
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  10. Solve, round to four decimal places if necessary:log4(x-9)=2 Answer: x-9=4^2 x-9=16 x=11 log4(z)+log4(z-3)=1 Answer: z+z-3=1
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    2. Lucy asked by Lucy
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