Question
Solve, round to four decimal places if necessary:
log4(x-9)=2
Answer:
x-9=4^2
x-9=16
x=11
log4(z)+log4(z-3)=1
Answer:
z+z-3=1
2z=4
z=2
Thanks for checking my work.
log4(x-9)=2
Answer:
x-9=4^2
x-9=16
x=11
log4(z)+log4(z-3)=1
Answer:
z+z-3=1
2z=4
z=2
Thanks for checking my work.
Answers
Answer:
x-9=4^2
x-9=16
x=11 BUT 16 PLUS 9 = 25
log A + log B = log (A+B) !!!!
log4 (z^2 - 3 z ) = 1
z^2 - 3 z = 4^1 = 4
z^2 -3 z -4 = 0
(z-4)(z+1) = 0
z = 4 or -1
x-9=4^2
x-9=16
x=11 BUT 16 PLUS 9 = 25
log A + log B = log (A+B) !!!!
log4 (z^2 - 3 z ) = 1
z^2 - 3 z = 4^1 = 4
z^2 -3 z -4 = 0
(z-4)(z+1) = 0
z = 4 or -1
log A + log B = log (A*B) !!!!
Related Questions
Solve log4 x + log4(x-2)=log4(15)
I know how do the example in my book but I don't know what I'...
Solve the equation algebraically. Round the result to three decimal places.
log4 x - log4(x-1)...
Which of the following options rewrites log4(9m3n) using the Quotient Rule of Logarithms, the Produc...
Which of the following options correctly rewrites log4 (x/5)
using the Quotient Rule of Logarith...