Question
log8-log4/log4-log2
Answers
assuming the usual carelessness with parentheses,
(log8-log4)/(log4-log2)
= (3log2 - 2log2)/(2log2-log2)
= 1
or,
log(8/4) / log(4/2) = log2/log2 = 1
(log8-log4)/(log4-log2)
= (3log2 - 2log2)/(2log2-log2)
= 1
or,
log(8/4) / log(4/2) = log2/log2 = 1
Related Questions
Solve log4 x + log4(x-2)=log4(15)
I know how do the example in my book but I don't know what I'...
Simply the following as far as possible.
1.log8 - log4*log6/log4
2.log8+log4
log4(2*256x^4)
i know that
log4(2)+log4(256)+log4(x^4)
=
log2^2(2)+4+4log4(x)
but now I am...
Which of the following options rewrites log4(9m3n) using the Quotient Rule of Logarithms, the Produc...