Solve log8-log4
3 answers
your answer is log2
That is the whole idea.
To multiply a and b add their logs
To divide, subtract
log b/a = log b - log a
the reason is
base^log x = x
if the base is 10 then
10^log x = x
10^log y = y
so
x y = 10^log x + 10^log y = 10^(logx+ log y)
so
log xy = log x + log y
To multiply a and b add their logs
To divide, subtract
log b/a = log b - log a
the reason is
base^log x = x
if the base is 10 then
10^log x = x
10^log y = y
so
x y = 10^log x + 10^log y = 10^(logx+ log y)
so
log xy = log x + log y
TYPO
x y = 10^log x * 10^log y = 10^(logx+ log y)
x y = 10^log x * 10^log y = 10^(logx+ log y)