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a 2.50-mole quatity of NOCL

a 2.50-mole quatity of NOCL was initially in a 1.50-L reaction chamber at 400 degrees celcius. after equilibrium was
1. 2 answers
2. asked by angel
3. 4,142 views
A 2.30 mole quantity of NOCl was initially in a 1.50 L reaction chamber at 400°C. After equilibrium was established, it was
1. 1 answer
2. asked by Anonymous
3. 1,032 views
1.25 mol of NOCl was placed in a 2.50 L reaction chamber at 427 celciciu degre . After equilibrium was reached, 1.1 mole of NOCl
1. 5 answers
2. asked by Abdela
3. 6,807 views
0.500 moles of NOCl is placed in a 1.00L vessel at 700K,and after the system comes to equilibrium,the concentration of the NOCl
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2. asked by Bob
3. 619 views
At 35°C, K = 1.6 10-5 mol/L for the following reaction.2 NOCl(g) 2 NO(g) + Cl2(g) Calculate the concentrations of all species
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2. asked by BETH
3. 717 views
The compound NOCl decomposes to nitric oxide and chlorine according to the following equation:2 NOCl (g) → 2 NO (g) + Cl2 (g)
1. 7 answers
2. asked by John
3. 1,247 views
what quatity of electricity will liberate 0.125 mole of dilule sodium chloride solution？(F=96500(mol-1)
1. 2 answers
2. asked by david
3. 389 views
Consider the following equilibrium.2 NOCl(g) ⇌ 2 NO(g) + Cl2(g) Determine Kc if 1.00 mol of NOCl(g) is initially placed in an
1. 3 answers
2. asked by jhope
3. 1,074 views
Unit 5 Activity 1: Intro to Equilibrium and Keq [5 marks]1. 0.32 moles of NOCl(g) was placed in a 2 L reaction vessel and found
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2. 37 views
Using this data,2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3 NO2(g) == NO(g) + ½ O2(g) Kc = 3.93 calculate a value for Kc for
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2. asked by Hannah
3. 783 views