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A 2.30 mole quantity of NOCl was initially in a 1.50 L reaction chamber at 400°C. After equilibrium was established, it was found that 20.0 percent of the NOCl had dissociated:
2NOCl(g) 2NO(g) + Cl2(g)
Calculate the equilibrium constant Kc for the reaction.
2NOCl(g) 2NO(g) + Cl2(g)
Calculate the equilibrium constant Kc for the reaction.
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Answered by
ayalew
12
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