Question

1.25 mol of NOCl was placed in a 2.50 L reaction chamber at 427 celciciu degre . After equilibrium was reached, 1.1 mole of NOCl remained. Calculate the equilibrium constant Kc for the reaction
............2NOCl ==> 2NO + Cl2
initial.....1.25.......0.....0
change.......-2x.......2x....x
equil......1.25-2x.....2x.....x

From problem, 1.25-2x =1.1 mols
Therefore, x = 0.075 mols
Convert x, 2x, and 1.25 to moles/L. M = moles/2.5L.
You now know (NO), (Cl2), and (NOCl).
Substitute into the Kc expression for NOCl and solve for Kc.
0.000432
where did you get this question from ?
5.6×10^-10
dr bobs response was correct, but for anyone who needs to go further, 2NOCl is 1.1, 2NO is 0.15, and Cl2 is 0.075 by x. To get Kc, it would be (0.15^2)(0.075)/(1.1^2), which equals 1.4x10^-3.

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