Asked by Abdela

1.25 mol of NOCl was placed in a 2.50 L reaction chamber at 427 celciciu degre . After equilibrium was reached, 1.1 mole of NOCl remained. Calculate the equilibrium constant Kc for the reaction

Answers

Answered by DrBob222
............2NOCl ==> 2NO + Cl2
initial.....1.25.......0.....0
change.......-2x.......2x....x
equil......1.25-2x.....2x.....x

From problem, 1.25-2x =1.1 mols
Therefore, x = 0.075 mols
Convert x, 2x, and 1.25 to moles/L. M = moles/2.5L.
You now know (NO), (Cl2), and (NOCl).
Substitute into the Kc expression for NOCl and solve for Kc.
Answered by seid temam
0.000432
Answered by Abdel
where did you get this question from ?
Answered by berhanu
5.6×10^-10
Answered by Ray
dr bobs response was correct, but for anyone who needs to go further, 2NOCl is 1.1, 2NO is 0.15, and Cl2 is 0.075 by x. To get Kc, it would be (0.15^2)(0.075)/(1.1^2), which equals 1.4x10^-3.
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