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Questions (12)
(1) MgCO3(s) ⟶ MgO(s) + CO2(g) ΔrH = 118.1 kJ mol−1
(2) Mg(s) + 12O2(g) ⟶ MgO(s) ΔfH =−601.7 kJ mol−1 What is the
4 answers
2,148 views
For the following reaction, Kc = 2.7×108 at 300 K.
3 H2(g) + N2(g) ⇌ 2 NH3(g) In an experiment carried out at 300 K, the
1 answer
663 views
Consider the following equilibrium.
2 NOCl(g) ⇌ 2 NO(g) + Cl2(g) Determine Kc if 1.00 mol of NOCl(g) is initially placed in an
3 answers
1,044 views
Consider the following reaction.
CaC2(s) + 2 H2O(l) ⇌ Ca(OH)2(aq) + C2H2(g) Which of the following represents the thermodynamic
6 answers
2,586 views
The decomposition reaction, X → products, has rate constant k = 0.00707 mol L−1 s−1 at a particular temperature. How long
1 answer
917 views
The reaction below is second-order in NO and first order in O2.
2 NO(g) + O2(g) ⟶ 2 NO2(g) When 5.00 mol of NO and 2.00 mol O2
5 answers
909 views
A(aq) + 2 B(aq) ⟶ 4 C(aq) + 4 D(aq)
What is the rate of production of C, in mol L−1 s−1, if the rate of production of D
2 answers
272 views
For the reaction below at 298.15 K, the standard enthalpy of reaction is ΔrH° = 41.6 kJ mol−1 and the thermodynamic
5 answers
1,240 views
Consider the process below. The normal boiling point of CH3CH2CH(OH)CH3 is 99 °C.
CH3CH2CH(OH)CH3(g, 128 °C, 1 atm) ⟶
1 answer
484 views
If it requires 115 J of heat to increase the temperature of 2.17 moles of a solid metal from 24.37 °C to 26.32 °C at constant
7 answers
364 views
Acetic acid is a weak acid with the formula , CH3COOH, the Ka for acetic acid is 1.76 x 10-5.
In aqueous solution, acetic acid
1 answer
1,327 views
What volume (in mL) of 0.190 M sodium thiosulphate, Na2S2O3, solution is needed to prepare 250.0 mL of 0.0140 M sodium
2 answers
699 views
Answers (16)
what do you mean?
so it will be: Kc = [Cl2][NO]^2 / [NOCl]^2 =0.9x0.9^2 / 0.9-1?
i mean K=[C2H2][Ca(OH)2]
oh i see, is it K=PC2H2[Ca(OH)2]
no i dont think thats right
so, 118x-601 + 2x601?
so it would be k=0.0088?
i think its: The entropy of the system increases: ΔS > 0. The entropy of the universe increases: ΔSuniv > 0. Work is done by the system on the surroundings. The process is thermodynamically irreversible. pls confirm
yeah, not sure how to solve it. ive subtracted the temp, but what do i do with the mols and J?
what would k be then?
still confused..
dGo = -RT*lnK for this would it be -8.135(298)ln(298)?
hmm never learned those, but thanks
thats what i thought, thanks!
a and c B D THESE ARE THE RIGHT AWNERES ENJOY ._.
dose anyone know the awnsers to Lesson 19: Unit Test Language Arts 6 A Unit 2: Characters and Conflict?