Asked by jhope
Consider the following reaction.
CaC2(s) + 2 H2O(l) ⇌ Ca(OH)2(aq) + C2H2(g)
Which of the following represents the thermodynamic equilibrium constant, K ?
K=[H2O]2[CaC2]PC2H2[Ca(OH)2]
K=PC2H2[Ca(OH)2][CaC2]
K=[C2H2][Ca(OH)2][H2O]2[CaC2]
K=PC2H2[Ca(OH)2]
K=[C2H2][Ca(OH)2]
K=[H2O]2[CaC2][C2H2][Ca(OH)2]
CaC2(s) + 2 H2O(l) ⇌ Ca(OH)2(aq) + C2H2(g)
Which of the following represents the thermodynamic equilibrium constant, K ?
K=[H2O]2[CaC2]PC2H2[Ca(OH)2]
K=PC2H2[Ca(OH)2][CaC2]
K=[C2H2][Ca(OH)2][H2O]2[CaC2]
K=PC2H2[Ca(OH)2]
K=[C2H2][Ca(OH)2]
K=[H2O]2[CaC2][C2H2][Ca(OH)2]
Answers
Answered by
DrBob222
This is basic stuff. What's your problem with this?
Answered by
sara
i just dont understand how to solve it. will it be K=[C2H2][Ca(OH)2][H2O]2[CaC2]?
Answered by
DrBob222
No. "pure" solids and "pure" liquids are not part of a K value.
BTW, please don't switch screen names. One name is all you need.
Another BTW, I think there are two answers that are correct.
BTW, please don't switch screen names. One name is all you need.
Another BTW, I think there are two answers that are correct.
Answered by
jhope
oh i see, is it K=PC2H2[Ca(OH)2]
Answered by
jhope
i mean K=[C2H2][Ca(OH)2]
Answered by
DrBob222
I think both of those are correct. Use pC2H2 if partial pressures are given and use M if mols/L are given
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