Varify the identity cscx(cscx-sinx)+sinx-cosx/sinx +

My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
1. 2 answers
2. asked by Jon
3. 950 views
Varify the identity cscx(cscx-sinx)+sinx-cosx/sinx + cot?
1. 1 answer
2. asked by clarence
3. 480 views
Verify the identity .(cscX-cotX)^2=1-cosX/1+cosX _______ sorry i cant help you (cscX-cotX)=1/sinX - cosX/sinX = (1-cosX)/sinX If
1. 0 answers
2. asked by Rose
3. 751 views
Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
1. 3 answers
2. asked by Anonymous
3. 965 views
Find a numerical value of one trigonometric function of x iftanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
1. 1 answer
2. asked by Lucy
3. 988 views
Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
1. 1 answer
2. asked by Anonymous
3. 1,381 views
Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
1. 4 answers
2. asked by Anonymous
3. 1,976 views
express in sinx1 1 ---------- + -------- cscx + cotx cscx - cotx and express in cosx 1 + cot x ------- - sin^2x cscx = 1/sinx so
1. 0 answers
2. asked by linds
3. 792 views
express this in sinx(1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B) express in cosx problem: is 1 +
1. 1 answer
2. asked by linds
3. 1,426 views
1) evaluate without a calculator: a)sin(3.14/4) b) cos(-3(3.14)/4) c) tan(4(3.14)/3) d) arccos(- square root of three/2) e)
1. 1 answer
2. asked by Emily
3. 1,514 views