The solubility products of AgCl

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  1. Equilibrium expression: AgCl(s) ⇌ Ag+(aq) + Cl-(aq) KSP = 1.8 x 10-10 The solubility of AgCl in: i) pure water: solubility =
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    2. JAY_ndabeh asked by JAY_ndabeh
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  2. Equilibrium expression: AgCl(s) ⇌ Ag+(aq) + Cl-(aq) KSP = 1.8 x 10-10 The solubility of AgCl in: i) pure water:ii) a 0.50 M
    1. answers icon 4 answers
    2. JAY_ndabeh asked by JAY_ndabeh
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  3. Calculate solubility of AgCl (in g/L) in a 6.5*10^-3 M silver Nitrate solution ksp= 1.8 * 10^-10(AgCl molecular mass is 143.3g)
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    2. Steve asked by Steve
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  4. Question 2What is the solubility of AgCl in 10 M NH3? The Kf of Ag(NH3)2+ from AgCl(s) in aqueous NH3 is 0.0031, which is for
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    2. Nevaeh asked by Nevaeh
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  5. Calculate solubility of AgCl (in g/L) in a 6.5*10^-3 M silver Nitrate solution ksp= 1.8 * 10^-10(AgCl molecular mass is 143.3g)
    1. answers icon 1 answer
    2. Steve asked by Steve
    3. views icon 809 views
  6. I do not quiet understand what you said. Could you show your work.What is the solubility of AgCl in 10 M NH3? The Kf of
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    2. Nevaeh asked by Nevaeh
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  7. What is the solubility of AgCl in 10 M NH3? The Kf of Ag(NH3)2+ from AgCl(s) in aqueous NH3 is 0.0031, which is for the balanced
    1. answers icon 1 answer
    2. Nevaeh asked by Nevaeh
    3. views icon 1,071 views
  8. The solubility products of AgCl and 𝐴𝑔3𝑃𝑂4 are 1.6 × 10−10 and 1.8 × 10−18, respectively. If 𝐴𝑔+ is
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    2. samantha sipioni asked by samantha sipioni
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  9. The presence of ammonia in a solution of AgCl will decrease the solubility of AgCl.True Or False
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    2. Katie asked by Katie
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  10. Explain how the differences in the solubility products of AgI and AgCl make thisexperiment possible. Include in your discussion
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    2. margaret asked by margaret
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