Asked by samantha sipioni
The solubility products of AgCl and π΄π3ππ4 are 1.6 Γ 10β10 and 1.8 Γ 10β18, respectively. If π΄π+ is added (without changing the volume) to 1.00 L of a solution containing 0.10 mol πΆπβ and 0.10 mol ππ4 3β, calculate the concentration of π΄π+ions (in mol/L) required to initiate
(a) the precipitation of AgCl and
(b) the precipitation of π΄π3ππ4
(a) the precipitation of AgCl and
(b) the precipitation of π΄π3ππ4
Answers
Answered by
DrBob222
What (Ag^+) is required to ppt AgCl and Ag3PO4 in separate solutions?
For AgCl it is (Ag^+) = (1.6E-10/0.1) = 1.6E-9 M
For Ag3PO4 it is (Ag^+) = (1.8E-18/0.1)^1/3 = 2.6E-6 M
(a) Therefore, Ag^+ added drop wise to the initial solution will ppt AgCl first when (Ag^+) = 1.6E-9 M and leave Ag3PO4 undisturbed.
(b) When (Ag^+) = 2.62E-6 M the Ag3PO4 will begin ppting.
For AgCl it is (Ag^+) = (1.6E-10/0.1) = 1.6E-9 M
For Ag3PO4 it is (Ag^+) = (1.8E-18/0.1)^1/3 = 2.6E-6 M
(a) Therefore, Ag^+ added drop wise to the initial solution will ppt AgCl first when (Ag^+) = 1.6E-9 M and leave Ag3PO4 undisturbed.
(b) When (Ag^+) = 2.62E-6 M the Ag3PO4 will begin ppting.
Answered by
Meshack
Well done
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