Question

Calculate solubility of AgCl (in g/L) in a 6.5*10^-3 M silver Nitrate solution ksp= 1.8 * 10^-10
(AgCl molecular mass is 143.3g) any idea on how to do this this is what i tried>


AgCl--> Ag + Cl

I 6.5*10^-3 0
C same x
E same x


ksp = [Ag][Cl]

(1.8 * 10^-10) = (6.5 * 10^-3)x

x = 2.77 * 10^-8 M


I don't know what to do next please help me thank you

Answer 1

see your other post above.