Calculate solubility of AgCl (in g/L) in a 6.510^-3 M silver Nitrate solution ksp= 1.8 10^-10

(AgCl molecular mass is 143.3g) any idea on how to do this this is what i tried>

AgCl--> Ag + Cl

I 6.5*10^-3 0
C same x
E same x

ksp = [Ag][Cl]

(1.8 * 10^-10) = (6.5 * 10^-3)x

x = 2.77 * 10^-8 M

I don't know what to do next please help me thank you

1 answer

see your other post above.

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Calculate solubility of AgCl (in g/L) in a 6.5*10^-3 M silver Nitrate solution ksp= 1.8 * 10^-10

Calculate solubility of AgCl (in g/L) in a 6.510^-3 M silver Nitrate solution ksp= 1.8 10^-10