Asked by Steve
Calculate solubility of AgCl (in g/L) in a 6.5*10^-3 M silver Nitrate solution ksp= 1.8 * 10^-10
(AgCl molecular mass is 143.3g) any idea on how to do this this is what i tried>
AgCl--> Ag + Cl
I 6.5*10^-3 0
C same x
E same x
ksp = [Ag][Cl]
(1.8 * 10^-10) = (6.5 * 10^-3)x
x = 2.77 * 10^-8 M
I don't know what to do next please help me thank you
(AgCl molecular mass is 143.3g) any idea on how to do this this is what i tried>
AgCl--> Ag + Cl
I 6.5*10^-3 0
C same x
E same x
ksp = [Ag][Cl]
(1.8 * 10^-10) = (6.5 * 10^-3)x
x = 2.77 * 10^-8 M
I don't know what to do next please help me thank you
Answers
Answered by
DrBob222
see your other post above.
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