Asked by macfailay
The solubility of AgCl in pure water is 0.000012 M. Calculate the value of solubility product constant
Answers
Answered by
DrBob222
...................AgCl ==> Ag^+ + Cl^-
I.................solid...........0...........0
C,,,,,,,,,,,,,,,,solid...........x...........x
E..................solid..........x...........x
Ksp = (Ag^+)(Cl^-) = (1.2E-5)(1.2E-5) = ?
I.................solid...........0...........0
C,,,,,,,,,,,,,,,,solid...........x...........x
E..................solid..........x...........x
Ksp = (Ag^+)(Cl^-) = (1.2E-5)(1.2E-5) = ?