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Simplify #1: cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx
Simplify #1:
cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
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Anonymous
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Simplify #1:
cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
1 answer
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Anonymous
1,411 views
My previous question:
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2 answers
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Jon
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Simplify #3:
[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1 answer
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Anonymous
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Find a numerical value of one trigonometric function of x if
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1 answer
asked by
Lucy
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1 answer
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1 answer
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Problem 1.
2 answers
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How do you verify the equation is an identity?
Tan^2x-tan^2y=sec^2x-sec^2y and, how do you factor and simplify,
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