MgCl2(aq) + 2 NaOH(aq) -->

  1. MgCl2(aq) + 2 NaOH(aq) --> Mg(OH)2(s) + 2 NaCl(aq)How many grams of Mg(OH)2 would form if 50.00 mL of 0.9750M NaOH were combined
    1. answers icon 1 answer
    2. Lauren asked by Lauren
    3. views icon 1,436 views
  2. MgCl2(aq) + 2 NaOH(aq) --> Mg(OH)2(s) + 2 NaCl(aq)How many grams of Mg(OH)2 would form if 50.00 mL of 0.9750M NaOH were combined
    1. answers icon 1 answer
    2. Lauren asked by Lauren
    3. views icon 1,163 views
  3. molecular equation, and net ionic equation ofK2SO4 + MgCl2 NiCl2 + NaOH MgCl2 + NaOH K2SO4 + NaOH Ba(OH)2 + NiCl2 Ba(OH)2 +
    1. answers icon 2 answers
    2. Anonymous asked by Anonymous
    3. views icon 1,958 views
  4. Predict whether or not a precipitate will form upon mixing 75.0 mL of a NaOH solution with pOH = 2.58 with 125.0 mL of a 0.018 M
    1. answers icon 2 answers
    2. Anonymous asked by Anonymous
    3. views icon 1,499 views
  5. In order to make 500.0mL of a 1.835 M MgCl2 solution, then _______g of MgCl2 is needed.Moles of MgCl2= (1.835M)(0.5L)=0.9175mol
    1. answers icon 1 answer
    2. Queen asked by Queen
    3. views icon 1,256 views
  6. With an equilibrium constant of k=1.3 if NaOH and MgCL2 are added in stoichiometric ratio and 1.2 mol of NaOH are present at
    1. answers icon 5 answers
    2. Bryce asked by Bryce
    3. views icon 472 views
  7. Which sample has the most solute?Question 15 options: 200. mL of 0.200 M MgCl2 150. mL of 0.250 M MgCl2 100. mL of 0.300 M MgCl2
    1. answers icon 1 answer
    2. Brendon asked by Brendon
    3. views icon 542 views
  8. suppose 23mL of NaOH was required. How much Carbonic Acid was neutralized?1L of .01 NaOH contains ____ mol NaOH? lmL of .01 NaOH
    1. answers icon 0 answers
    2. Anonymous asked by Anonymous
    3. views icon 1,270 views
  9. Write the balanced dissociation equation for MgCl2. (1 mark)MgCl2(s) + H2O(l) ==> Mg^+2(aq) + 2Cl^-(aq) b) In 300.0 mL of a 0.50
    1. answers icon 1 answer
    2. JOEY asked by JOEY
    3. views icon 1,730 views
  10. How many milliliters (ml) of 5 M MgCl2 must be added to 25 ml of a 0.5 M MgCl2 solutionto produce 1500 ml with a final MgCl2
    1. answers icon 1 answer
    2. Abass asked by Abass
    3. views icon 2,473 views